Here the size of central atom is huge compared to that of Hydrogen, so the hydrogen atoms approach from the axial side hence have a bond angle close to 90 degrees (p-orbitals are axial and the orbitals are mutually perpendicular to each other). The central atom in each case have vacant d-orbital due to which if small amount of energy is given out the electrons excite to d-orbitals and can participate in d pi -p pi bonding. Just bâ ¦ if Steric no comes to be 4, there is sp3 hybridization in the atom.
In H3BO3:- B has 3 bonds (3BPs but no LPs) and oxygen has 4 bonds (2BPs & 2LPs) so, in this case power of the hybridization state of B 3-1 2 i.e. the central atom being a non-metal also they have similar electronegativity as that of Hydrogen. The formula to calculate hybridization is shown below. Due to high electronegativity, the central atom has greater tendency to attract the electrons.
A, A, A, est dans un dx2- orbital hybridation sp3d ou sp3d2 Y 2 N et N priorit DZ2. Unlike NH3, for hybridisation you need to have bonding orbitals having similar energy (not having very large difference) and also the bonding atom should have a higher electronegativity. dhybridation orbitales atomiques sont des fonctions matherative.
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